响应式网站设计的现状计算机关于网站开发的证书

没做出来 看了解析 但是思路想到了 就是只能调整链表顺序，正确答案是 把链表变成两条单链表，分别从两侧走向中间拿两个指针 分别指向两头 ，往中间走 中途有不一样的就返回false,

private static  boolean  handle(Node head){int size = size(head);Node[] reserve = reserve(head, size / 2);Node left = reserve[0];Node right = reserve[1];while(left!=null&&right!=null){Integer leftvalue=left.getValue();Integer rightValue=right.getValue();if(leftvalue!=rightValue){return false;}left=left.next;right=right.next;}return true;}

其中一个方法是反转链表

private static Node[] reserve(Node head,int start){Node[] result=new Node[2];Node pre=null;Node current=head;int count=0;while(current!=null){if(count>start) {Node next = current.next;current.next = pre;pre = current;current = next;continue;}current=current.next;count++;}result[0]=pre;result[1]=head;return result;}

获取链表长度 方便到时候确定从哪里开始反转

private static int size(Node head){Node current=head;int count=0;while(current!=null){count++;current=current.next;}return count;}

结束