惠州网站建设方案外包深圳哪家做网站好

题目

思路

核心思想是枚举
首先利用set记录每一种颜色
然后依次从set取出一种颜色作为targetColor，遍历房子
如果当前房子的颜色和targetColor不相同，就以当前房子为起点，往后长度为k的区间都涂成targetColor，并且需要的天数递增1
否则就一直向下遍历直到所有房子遍历完

代码

#include <bits/stdc++.h>
#define MAX 1e5;
using namespace std;
int main() {int t;scanf("%d", &t);for(int i = 0; i < t; i++) {int n, k;scanf("%d %d", &n, &k);set<int> mySet;vector<int> myVector;for(int i = 0; i < n; i++) {int data;scanf("%d", &data);mySet.insert(data);myVector.push_back(data);}int minDay = MAX;for(const auto& targetColor : mySet) {// printf("target color is %d\n", targetColor);int day = 0;int i = 0; while(i < n) {// printf("current house id is %d\n", i);// printf("current color of hourse is %d\n", myVector[i]);if(myVector[i] != targetColor) {i = i + k;day++;}else {i++;}}if(day < minDay) {minDay = day;}}printf("%d\n", minDay);}return 0;
}